This is what the Filecard Z1-3 looked like initially
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For 1+i
1+i=rcos(theta)+rsin(theta)

r=sqrt(1^2 + 1^2) = sqrt(2)
theta= pi/4 since sqrt(2)cos(pi/4)=1 and sqrt(2)sin(pi/4)=1

For x+iy,
2cos(pi/3)+i2sin(pi/3)=x+iy
x=1
y= sqrt(3)
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This is a partial edit into proper LaTeX 
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Solve for $r,\theta$

$1+i=r \cos\theta+r\sin\theta$

$r=\sqrt{1^2 + 1^2} = \sqrt 2$

$\theta= \pi/4 $ since $\sqrt 2 \cos \pi/4=1$

 and $\sqrt 2\sin \pi/4 =1$


For x+iy,
2cos(pi/3)+i2sin(pi/3)=x+iy
x=1
y= sqrt(3)
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